
Lv.1
在 编程猫创新编程(NOC)初赛备考攻略·第二期 中回复
n1 = 1
n2 = 1
mouths = 3
while (mouths <= 12):
n3 = (n1 + n2)
mouths += 1
n1 = n2
n2 = n3
print('兔子总数为',(n3 * 2))2019-05-07T21:15:47 点赞:1
在 编程猫创新编程(NOC)初赛备考攻略·第一期 中回复
import turtle
import time
t = turtle.Pen()
t.speed(0)
for i in range(10):
for i in range(4):
t.forward(100)
t.left(90)
t.left(36)
time.sleep(3)
t.clear()
for i in range(5):
t.forward(200)
t.right(144)
time.sleep(3)
t.clear()
for i in range(4):
t.forward(100)
t.right(90)
for i in range(2):
t.forward(100)
t.left(150)
t.forward(((100 * 3) / 8))
t.left(30)
t.right(90)
for i in range(2):
t.forward(100)
t.right(120)
t.forward(((100 * 3) / 8))
t.right(60)
turtle.done()
2019-05-07T21:18:09 点赞:1