用户:罗文浩GGFh查看:0 回复:0 评论:0 创建时间:2023-07-28T09:07:08
【作品展示】

【作品介绍】
哈哈
【作品源代码】
# -*- coding=utf-8 -*-
import pygame
from pygame.locals import KEYDOWN
import random
w, h = 800, 600 #w----width h--hight
pygame.init()
screen = pygame.display.set_mode((w, h))
white = 255, 255, 255
black = 111, 111, 111
myfont = pygame.font.Font(None, 80)
diff_ticks = 20
ticks = pygame.time.get_ticks() + diff_ticks
word_diff_ticks = 1000
word_ticks = pygame.time.get_ticks() + word_diff_ticks
zm = 0
def get_random_word():
global zm
color = (random.randint(0, 255), random.randint(
0, 255), random.randint(0, 255)) # 颜色随机
x = random.randint(100, w-100) # x坐标从左右边距各100之间随机
y = 0
word = 65 + zm%26
zm += 1
return x, y, word, color
arr = []
arr.append(get_random_word())
clear_word = 0
level = 1
pygame.display.set_caption('typing level:%d' % level)
game_state = 1 # 1.进行中 2.游戏失败
sign = 1
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
exit()
if game_state == 1 and len(arr) > 0 and event.type == KEYDOWN:
if event.key == arr[0][2]+32: # 大小写字母差32
arr.pop(0)
clear_word += 1
if clear_word >= level*10:
level += 1
pygame.display.set_caption('typing level:%d' % level)
diff_ticks = diff_ticks*0.9
word_diff_ticks = word_diff_ticks*0.95
screen.fill((255, 255, 255))
for i in range(len(arr)): # 绘制这些字母
x, y, word, c = arr[i]
#if i == 0 and sign:
if i == 0:
#c = (random.randint(0, 255), random.randint(0, 255), random.randint(0, 255))
c = (200, 100, 100)
textImage = myfont.render(chr(word), True, c)
screen.blit(textImage, (x, y))
if game_state == 2:
textImage = myfont.render("Level%d fail" % level, True, (255, 0, 0))
sw, sh = textImage.get_size()
screen.blit(textImage, ((w-sw)/2, (h-sh)/2)) # 居中显示
if game_state == 1:
if pygame.time.get_ticks() >= word_ticks: # 计时增加新字母
word_ticks += word_diff_ticks
arr.append(get_random_word())
if pygame.time.get_ticks() >= ticks:
ticks += diff_ticks
sign = 1-sign
for i in range(len(arr)):
x, y, word, c = arr[i]
arr[i] = (x, y+1, word, c)
if len(arr) > 0 and arr[0][1] > h:
game_state = 2
pygame.display.update()
【提示】
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