用户:一点都不难查看:0 回复:0 评论:0 创建时间:2022-05-20T19:32:39
【作品展示】

【作品介绍】
本游戏可以帮助游戏玩家解决手速不够快的问题,使我们玩出更获得自己!
【作品源代码】
import pgzrun
from random import randint
WIDTH = 640
HEIGHT = 480
score1 = 0
score2 = 0
button1 = Actor("button1_on")
button1.pos = WIDTH / 4, HEIGHT / 2 + 60
button2 = Actor("button2_on")
button2.pos = WIDTH - WIDTH / 4, HEIGHT / 2 + 60
time_left = 5
game_over = False
def draw():
screen.fill("lightblue")
button1.draw()
button2.draw()
screen.draw.text("press S: " + str(score1), color="white",
center=(WIDTH / 4, 150), fontsize=50)
screen.draw.text("press L: " + str(score2), color="white"
, center=(WIDTH - WIDTH / 4, 150), fontsize=50)
screen.draw.text("Time Left: " + str(time_left), color="white",
center=(WIDTH / 2, 40),
fontsize=50)
if game_over:
screen.fill("lightblue")
screen.draw.text("player S: " + str(score1),
center = (WIDTH / 4, 120 ), fontsize=50)
screen.draw.text("player L: " + str(score2),
center=(WIDTH - WIDTH / 4, 120),
fontsize=50)
if score1 >score2:
winner = "The winner is piayer S!"
elif score1 < score2:
winner = "The winner is piayer L!"
else:
winner = "It's a tie!"
screen.draw.text(winner, center=(WIDTH / 2, HEIGHT / 2),
fontsize=60)
def on_key_down(key):
global score1, score2
if not game_over:
if key == key.S:
button1.image = "button1_off"
score1 += 1
if key == key.L:
button2.image = "button2_off"
score2 += 1
def on_key_up(key):
if key == key.S:
button1.image = "button1_on"
if key == key.L:
button2.image = "button2_on"
def update_time_left():
global time_left, game_over
if score1 > 0 or score2 > 0:
if time_left > 0:
time_left -= 1
else:
game_over= True
clock.schedule_interval(update_time_left, 1.0)
pgzrun.go()
【提示】
部分含有Python第三方库相关内容的作品,在海龟编辑器网页端无法运行哦!如遇到这种情况,可以打开下面的链接,下载海龟编辑器客户端:
https://python.codemao.cn