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【作品展示】

 

【作品介绍】

数字1是剪刀

数字2是石头

数字3是布

看看你是否能战胜电脑，取得胜利呢？

 

【作品源代码】

import turtle
import random

myscreen = turtle.Screen()
mypen = turtle.Pen()
mypen.hideturtle()
mypen.penup()
mypen.goto(-122.5,0)
mypen.pendown()
count = 0
p_win = 0
c_win = 0
flag = False
while count < 10:
    player = int(myscreen.textinput("剪刀1-石头2-布3","请输入拳名对应的数字:"))
    
    if player < 1 or player > 3:
        count = count + 1
        
    computer = random.randint(1,3)

    if player == 1:
        print("玩家出了：剪刀")
    elif player == 2:
        print("玩家出了：石头")
    elif player == 3:
        print("玩家出了：布")
    else:
        print("玩家输入数字超出范围")
        flag = True

    if computer == 1:
        print("计算机出了：剪刀")
    elif computer == 2:
        print("计算机出了：石头")
    else: 
        print("计算机出了：布")
    

    #判断胜负
    if player == computer or flag:
        print("此局是平局或废局")
        mypen.pencolor("gray")
        mypen.dot(20)
        flag = False
    elif player == 1 and computer == 3 or player == 2 and computer == 1 or  player == 3 and computer == 2:
        print("此局玩家胜")
        p_win = p_win + 1
        mypen.pencolor("darkgreen")
        mypen.dot(20)
    elif player == 3 and computer == 1 or player == 1 and computer == 2 or  player == 2 and computer == 3:
        print("此局计算机胜")
        c_win = c_win + 1
        mypen.pencolor("red")
        mypen.dot(20)
    mypen.penup()
    mypen.forward(25)
    mypen.pendown()
    count = count + 1
    print("---------------")
    
print("玩家的胜局为：",p_win)
print("计算机的胜局为：",c_win)
turtle.done()

 

【提示】

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https://python.codemao.cn