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ML愛意隨風起查看:0 回复:2 评论:0 创建时间:2021-05-31T18:09:34

【作品展示】

【作品介绍】

可以电脑判胜负

一局完成后，在对话框里输入数字1再来一盘

【作品源代码】

import turtle
turtle.title("五子棋")

iLine = 19   #网格行列数
iHalf = 9    #网格行列数的一半
H = 30       #间隔距离点数
runFlag = 1  #第一个下棋者为1，第二个为-1
isWin = 0    #是否已经胜出
chessData = [[0 for i in range(iLine)]for i in range(iLine)] #落子数据，0为未下，1白，-1红

StartX = -iHalf*H  #网格起始左上角X
StartY = iHalf*H  # 网格起始左上角Y

#检测是否已经五子连珠
def checkFive(row, col, nFlag):
    iPcs = 0
    for N in range(9):
        if col-4+N < 0:
            continue
        if col-4+N > iLine-1:
            break
        if chessData[row][col-4+N] == nFlag:
            iPcs = iPcs + 1
            if iPcs > 4:
                return iPcs
        else:
            iPcs = 0

    iPcs = 0
    for N in range(9):
        if row-4+N < 0:
            continue
        if row-4+N > iLine-1:
            break
        if chessData[row-4+N][col] == nFlag:
            iPcs = iPcs + 1
            if iPcs > 4:
                return iPcs
        else:
            iPcs = 0

    iPcs = 0
    for N in range(9):
        if row-4+N < 0 or col-4+N < 0:
            continue
        if row-4+N > iLine-1 or col-4+N > iLine-1:
            break
        if chessData[row-4+N][col-4+N] == nFlag:
            iPcs = iPcs + 1
            if iPcs > 4:
                return iPcs
        else:
            iPcs = 0

    iPcs = 0
    for N in range(9):
        if row-4+N < 0 or col+4-N < 0:
            continue
        if row-4+N > iLine-1 or col+4-N > iLine-1:
            break
        if chessData[row-4+N][col+4-N] == nFlag:
            iPcs = iPcs + 1
            if iPcs > 4:
                return iPcs
        else:
            iPcs = 0

    return 0

#响应鼠标点击
def getPos(x, y):
    global runFlag
    global chessData
    global isWin

#    print(x, y)
#已经决出胜负了
    if isWin >0:
        return
#限制下棋区域        
    if y < -iHalf*H-5 or y > iHalf*H+5:
         return
    if x < -iHalf*H-5 or x > iHalf*H+5:
         return
#允许稍微一点点偏差
    if y > 0:
         y = y+H/3
    else:
         y = y-H/3

    if x > 0:
         x = x+H/3
    else:
         x = x-H/3
#换算出以中心为0，0的行列值         
    row = int(y/H)
    col = int(x/H)
#要转换成左上角为0，0的数组
#要放棋的位置上已经有棋了
    if chessData[iHalf-row][iHalf+col] != 0:
        return

#    print(H*col, H*row, runFlag)
    strWin = "白方"
    if runFlag > 0:
       wmyPen.pencolor("#ff0000")
       runFlag = -1
       strWin = "红方"
    else:
       wmyPen.pencolor("#ffffff")
       runFlag = 1
       strWin = "白方"
    chessData[iHalf-row][iHalf+col] = runFlag
    isWin = checkFive(iHalf-row, iHalf+col, runFlag)

    wmyPen.penup()
    wmyPen.goto(H*col, H*row)
    wmyPen.pendown()
    wmyPen.dot(20+isWin*5)
    wmyPen.penup()
    if isWin==5:
        if (turtle.numinput('你赢了', strWin+'赢了，再来一盘吗?请输入数字1') == 1):
            isWin = 0
            drawLine()

    return

def cursorxy(event):
    x = event.x - 240
    y = 180 - event.y
    return



#画棋盘
def drawLine():
#初始化变量    
    runFlag = 1  # 第一个下棋者为1，第二个为-1
    isWin = 0
    for i in range(iLine):
        for j in range(iLine):
            chessData[i][j] = 0

#画个正方形清空屏幕
#    turtle.clearscreen() #这个不安全，不好用
    scr.bgpic("fivechess.gif")  # 不认识jpg
    # turtle.bgcolor("#ffd565")
    wmyPen.begin_fill()
    wmyPen.fillcolor("#ffd565")
    wmyPen.pencolor("#ffd565")  # 255,213,102
    wmyPen.penup()
    wmyPen.goto(H*(iHalf+1), -H*(iHalf+1))
    wmyPen.pendown()
    wmyPen.left(45)
    wmyPen.circle(H*(iHalf+1)*1.414, steps=4)
    wmyPen.right(45)
    wmyPen.end_fill()

    wmyPen.pencolor("#401000")
    wmyPen.penup()
    wmyPen.goto(-10, iHalf*H+15)
    wmyPen.pendown()
    wmyPen.write("五子棋")
    wmyPen.penup()

#奇怪，必须要手工多画一条，否则就看不到第一条线===================
    wmyPen.pencolor("#401000")
    wmyPen.goto(StartX, StartY)
    wmyPen.pendown()
    wmyPen.forward(H*(iLine-1))
    wmyPen.penup()
    # 画横线
    for N in range(iLine):
        wmyPen.goto(StartX, StartY-N*30)
        wmyPen.pendown()
        wmyPen.forward(H*(iLine-1))
        wmyPen.write('  '+str(N+1))
        wmyPen.penup()

    #画竖线
    wmyPen.right(90)
    for N in range(iLine):
        wmyPen.goto(StartX+N*30, StartY)
        wmyPen.pendown()
        wmyPen.write(str(N+1))
        wmyPen.forward(H*(iLine-1))
        wmyPen.penup()
    wmyPen.left(90)
#正中心画个点
    wmyPen.setpos(0, 0)
    wmyPen.pendown()
    wmyPen.dot(5)
    wmyPen.penup()
    return

#***************正文开始**************************#
# 五子棋 (电脑判胜负)
# 20200312 吴铭杨
#************************************************#

scr = turtle.getscreen()    # 获取当前的屏幕/画布
scr.setup(喵0, 喵0)
turtle.Turtle().screen.delay(0)  # 取消画布延迟

wmyPen = turtle.Pen()
wmyPen.speed(0)
#画棋盘
drawLine()

#定义响应鼠标事件
scr.cv.bind("", cursorxy)
scr.onclick(getPos, btn=1)

#space 空格重来,重画棋盘
scr.onkey(drawLine, "space")
scr.listen()

#海龟窗口停留
turtle.done()

【提示】

部分含有Python第三方库相关内容的作品，在海龟编辑器网页端无法运行哦！如遇到这种情况，可以打开下面的链接，下载海龟编辑器客户端：

https://python.codemao.cn

我需要复制粘贴

import pygame,sys#导入模块
pygame.init()#游戏初始化
pygame.mixer.init()
pygame.font.init()#汉字初始化
screen = pygame.display.set_mode((650,450))#创建游戏窗口
pygame.display.set_caption("五子棋")#设置游戏窗口的标题
pos=[]#记录棋盘上每一个点的坐标
x=10#记录点的x坐标
y=10#记录点的y坐标
p=[]#记录点的地图位置
n=0#判断棋子的颜色
color=[]#记录棋子的颜色
map1=[]#判断哪些项有点
i=0#判断胜负查看每一个点的循环变量
for a in range(16):#表示棋盘的行的点
    for a in range(16):#表示棋盘列的点
        pos.append((x,y))#将点的位置用元祖的方式记录到列表
        map1.append(0)#添加元素0代表点，1代表白棋，2代表黑棋
        x+=30#记录下一个点
    x=10#记录下一行的第一个
    y+=30#记录下一行
pygame.mixer.music.load("5a41_37f5_ac53_b2f6f7c0ea87d23a393503caa67a2c5f.mp3")
while True:#游戏循环
    if pygame.mixer.music.get_busy()==False:
        pygame.mixer.music.play()
    x=10#重设x坐标
    y=10#重设y坐标
    screen.fill((139,69,19))#设置为棋盘的颜色
    for event in pygame.event.get():#遍历所有按键
        if event.type == pygame.QUIT:#如果按下关闭键
            pygame.quit()#关闭窗口
            sys.exit()#关闭程序
        if event.type==pygame.MOUSEBUTTONDOWN:#判断是否点击鼠标
            for b in range(len(pos)):#遍历所有的点的位置
                #设置一个虚拟的圆，判断是否鼠标点击每个圆中
                if pos[b][0]-15<pygame.mouse.get_pos()[0] and pos[b][0]+15>pygame.mouse.get_pos()[0]:
                    if pos[b][1]-15<pygame.mouse.get_pos()[1] and pos[b][1]+15>pygame.mouse.get_pos()[1]:
                        if n==0:
                            n+=1
                            p.append(b)#添加点的项
                        if b!=p[-1]:
                            n+=1
                            p.append(b)#添加点的项
                        if n%2==0:#判断奇偶数
                            color.append((255,255,255))#将棋子颜色添加到列表
                            map1[b]=1
                        else:
                            color.append((0,0,0))
                            map1[b]=2
                        break
    for a in range(14):#表示棋盘行的点
        for a in range(15):#表示棋盘列的点
            pygame.draw.rect(screen,(0,0,0),(x,y,30,30),1)#绘制矩形
            x+=30#绘制下一个圆
        x=10#绘制下一行的第一个的圆
        y+=30#绘制下一行的圆
    pygame.draw.circle(screen,(255,0,0),(pygame.mouse.get_pos()[0]+5,pygame.mouse.get_pos()[1]+5),15,1)
    i+=1
    #绘制一个跟随鼠标的圆
    for c in range(len(p)):#判断有多少个点，将这些点都绘制出来
        pygame.draw.circle(screen,color[c],pos[p[c]],15,0)#绘制圆形
    screen.blit(pygame.font.SysFont("simhei",25).render("棋子数量：   "+str(n),0,(255,255,0)),(466,10))
    if i==250:#看循环是否结束
        i=0#重新检测
    #判断横
    if map1[i]==1 and map1[i+1]==1 and map1[i+2]==1 and map1[i+3]==1 and map1[i+4]==1:
        print("白棋赢")
        break
    if map1[i]==2 and map1[i+1]==2 and map1[i+2]==2 and map1[i+3]==2 and map1[i+4]==2:
        print("黑棋赢")
        break
    #判断竖
    if map1[i]==1 and map1[i+16]==1 and map1[i+32]==1 and map1[i+48]==1 and map1[i+喵]==1:
        print("白棋赢")
        break
    if map1[i]==2 and map1[i+16]==2 and map1[i+32]==2 and map1[i+48]==2 and map1[i+喵]==2:
        print("黑棋赢")
        break
    #判断反斜
    if map1[i]==1 and map1[i+16+1]==1 and map1[i+32+2]==1 and map1[i+48+3]==1 and map1[i+喵+4]==1:
        print("白棋赢")
        break
    if map1[i]==2 and map1[i+16+1]==2 and map1[i+32+2]==2 and map1[i+48+3]==2 and map1[i+喵+4]==2:
        print("黑棋赢")
        break
    #判断斜
    if map1[i]==1 and map1[i+16-1]==1 and map1[i+32-2]==1 and map1[i+48-3]==1 and map1[i+喵-4]==1:
        print("白棋赢")
        break
    if map1[i]==2 and map1[i+16-1]==2 and map1[i+32-2]==2 and map1[i+48-3]==2 and map1[i+喵-4]==2:
        print("黑棋赢")
        break
    #显示棋子数量，因为一共256个交叉点，所以空三格
    pygame.display.flip()#刷新游戏

KIHIO

def jd(x):
    try:
        x = float(x)
    except ValueError:
        return 0
    if x-(float(int(x))) > 0:
        return 0
    x = int(x)
    if x < 1 or x > 10:
        return 0
    return x


def sy(a, b, c, a2, b2, c2, s):
    x = 0
    while x <= a2:
        y = 0
        while y <= b2:
            n = 0
            lxh = 0
            lxb = 0
            while n <= c2:
                if s[x+y+n] == '黑':
                    lxh += 1
                else:
                    lxh = 0
                if s[x+y+n] == '白':
                    lxb += 1
                else:
                    lxb = 0
                n += c
            if lxb == 5:
                return 0
            if lxh == 5:
                return 2
            y += b
        x += a
    return 1


def xsy(xx, xs, yx, ys, js, js2, s):
    x = xx
    while x <= xs:
        y = yx
        while y <= yx:
            lxb = 0
            lxh = 0
            n = 0
            while n <= 4:
                if s[(y+n*js2)*10+x+n*js] == '黑':
                    lxh += 1
                else:
                    lxh = 0
                if s[(y+n*js2)*10+x+n*js] == '白':
                    lxb += 1
                else:
                    lxb = 0
                n += 1
            if lxb == 5:
                return 0
            if lxh == 5:
                return 2
            y += 1
        x += 1
    return 1


print("棋盘为10*10。")
s = []
a = 0
while a < 100:
    s.append('无')
    a += 1
print("你告诉我黑棋还是白棋先下？（输入A代表黑，输入B代表白）：")
while True:
    hb = input()
    if hb != 'A' and hb != 'B':
        print("输入错误，请重试：")
    else:
        break
b = 0
while True:
    f = 0
    fh = 0
    hqs = 0
    bqs = 0
    if sy(10, 1, 1, 90, 5, 4, s) == 2:
        hqs = 1
    if sy(1, 10, 10, 9, 50, 40, s) == 2:
        hqs = 1
    if sy(10, 1, 1, 90, 5, 4, s) == 0:
        bqs = 1
    if sy(1, 10, 10, 9, 50, 40, s) == 0:
        bqs = 1
    if xsy(0, 5, 0, 5, 1, 1, s) == 2:
        hqs = 1
    if xsy(4, 9, 4, 9, -1, -1, s) == 2:
        hqs = 1
    if xsy(0, 5, 0, 5, 1, 1, s) == 0:
        bqs = 1
    if xsy(4, 9, 4, 9, -1, -1, s) == 0:
        bqs = 1
    if xsy(0, 5, 4, 9, 1, -1, s) == 2:
        hqs = 1
    if xsy(0, 5, 4, 9, 1, -1, s) == 0:
        bqs = 1
    if xsy(4, 9, 0, 5, -1, 1, s) == 2:
        hqs = 1
    if xsy(4, 9, 0, 5, -1, 1, s) == 0:
        bqs = 1
    while f < 100:
        k = 0
        bs = ' '
        while k < 10:
            if k == 0:
                bs = s[f+k]
            else:
                bs = bs+' '+s[f+k]
            k += 1
        print(bs)
        f += 10
    if hqs == 1:
        print("黑棋赢！")
        break
    if bqs == 1:
        print("白棋赢！")
        break
    if hb == 'A':
        if b % 2 == 0:
            jhb = 'A'
        else:
            jhb = 'B'
    else:
        if b % 2 == 0:
            jhb = 'B'
        else:
            jhb = 'A'
    if jhb == 'A':
        print("黑棋的x坐标（从左到右，1~10）：")
        while True:
            x = input()
            if jd(x) == 0:
                print("输入错误，请重试：")
            else:
                x = jd(x)
                break
        print("黑棋的y坐标（从上到下，1~10）：")
        while True:
            y = input()
            if jd(y) == 0:
                print("输入错误，请重试：")
            else:
                y = jd(y)
                break
        if (s[(y-1)*10+x-1] == '黑') or (s[(y-1)*10+x-1] == '白'):
            print("禁止重叠，下次做决策看棋盘现状。")
            fh = 1
        else:
            s[(y-1)*10+x-1] = '黑'
    else:
        print("白棋的x坐标（从左到右，1~10）：")
        while True:
            x = input()
            if jd(x) == 0:
                print("输入错误，请重试：")
            else:
                x = jd(x)
                break
        print("白棋的y坐标（从上到下，1~10）：")
        while True:
            y = input()
            if jd(y) == 0:
                print("输入错误，请重试：")
            else:
                y = jd(y)
                break
        if (s[(y-1)*10+x-1] == '黑') or (s[(y-1)*10+x-1] == '白'):
            print("禁止重叠，下次做决策看棋盘现状。")
            fh = 1
        else:
            s[(y-1)*10+x-1] = '白'
    if fh == 0:
        b += 1

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python五子棋游戏代码

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