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一汪查看:0 回复:0 评论:0 创建时间:2021-05-16T15:16:43
【作品展示】

【作品介绍】
我的星际穿越第二部,用交互的方式通过输入宇宙飞船的x和y坐标来控制飞船穿越黑洞的位置。
【作品源代码】
import turtle
turtle.bgcolor('black')
turtle.speed(0)
turtle.delay(0)
mypen = turtle.Pen()
mypen.hideturtle()
# 黑洞
def draw_blackhole(holesize):
# 中心的圆
mypen.pendown()
outside = holesize
mypen.color("lightyellow")
mypen.dot(outside)
mypen.color("black")
mypen.dot(outside-outside/5)
inside = (outside-outside/4)
mypen.color("lightyellow")
mypen.dot(inside)
mypen.color("black")
mypen.dot(inside - 5)
#线
#mypen.penup()
mypen.left(180)
mypen.forward(outside)
mypen.pendown()
mypen.color("lightyellow")
mypen.left(180)
mypen.forward(outside*2)
mypen.right(180)
mypen.forward(outside*2-outside/8)
mypen.left(180)
mypen.pensize(5)
mypen.forward(outside*2-outside/8*2)
mypen.left(180)
mypen.forward(outside/8)
mypen.pensize(10)
mypen.forward(outside+outside/2)
# 宇宙飞船
def draw_flyboat(x, y):
mypen.pencolor('lightgrey')
mypen.penup()
#mypen.right(90)
#mypen.forward(190)
mypen.goto(x, y)
mypen.pendown()
mypen.left(90)
mypen.pensize(5)
num = (360 / 12)
i = 0
while (i < 12):
mypen.forward(20)
mypen.left(90)
mypen.forward(20)
mypen.left(90)
mypen.forward(20)
mypen.left(90)
mypen.forward(20)
mypen.left(90)
mypen.forward(20)
mypen.right(num)
i = (i + 1)
mypen.right(70)
mypen.forward(30)
mypen.right(90)
mypen.forward(8)
mypen.left(90)
mypen.forward(16)
mypen.left(90)
mypen.forward(16)
mypen.left(90)
mypen.forward(16)
mypen.left(90)
mypen.forward(8)
draw_blackhole(350)
x = int(input("请输入宇宙飞船的x坐标(-350~350):"))
y = int(input("请输入宇宙飞船的y坐标(-350~350):"))
draw_flyboat(x, y)
turtle.done()
【提示】
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