用户:
一个路过的吃瓜人查看:0 回复:0 评论:0 创建时间:2021-05-05T17:33:52
【作品展示】

【作品介绍】
有星星,有宇宙仓,有地球
【作品源代码】
import turtle
mypen = turtle.Pen()
num = int(input('输入1~4切换背景'))
if num == 0 :
print('切换无效')
elif num < 5 :
print('切换中')
if num == 1 :
mypen.pencolor('tomato')
mypen.dot(1234)
print('切换成功')
elif num == 2 :
mypen.dot(1234)
print('切换成功')
elif num == 3 :
mypen.pencolor('yellow')
mypen.dot(1234)
print('切换成功')
else:
mypen.pencolor('green1')
mypen.dot(1234)
print('切换成功')
else:
print('切换无效')
print('正在为您自动添加星星')
mypen.pencolor('white')
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = 0
while i < 5:
mypen.right(89)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(43)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 6 :
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(20)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(50)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(20)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
a = 0
a = "t"
i = 0
while i < 4 :
mypen.right(4)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(60)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(20)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
i = 0
while i < 4 :
mypen.right(120)
mypen.penup()
mypen.forward(20)
mypen.pendown()
mypen.dot(5)
i = i + 1
input('要加飞行厂吗t.要.s不要')
if a == "t" :
mypen.penup()
mypen.pencolor("black")
mypen.goto(0, 0)
mypen.pendown()
mypen.pencolor('white')
mypen.dot(15)
mypen.pencolor('coral')
mypen.dot(10)
if a == "s":
print('要加入地球吗i.要.n.不要')
input('要加入地球吗t.要.s不要')
if a == "t":
mypen.pencolor('gold')
mypen.penup()
mypen.goto(0,-230)
mypen.pendown()
mypen.dot(100)
mypen.penup()
mypen.goto(0, 0)
if a == "s":
print("结束")
turtle.done()
【提示】
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