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【Python作品分享】【攻破防】【别再意图】【作品秀】

用户:12345lcy12345lcy查看:0 回复:0 评论:0 创建时间:2021-02-18T18:52:50


【作品展示】

center_image

 

【作品介绍】

希望给赞

不能说我了

 

【作品源代码】

import turtle
import random

__Pen = turtle.Pen()


print('我无语了你们据然说我。我希望有点赞')

myscreen = turtle.Screen()
t = turtle.Pen()
t.hideturtle()
count = 0
p_win = 0
c_win = 0
flag = False
while (count < 10):
    player = int(turtle.textinput('攻1—2防—3破', ' 攻克破 防克攻 破克防 请输入对应的数字 只能填1~3'))
    computer = random.randint(1, 3)
    count = (count + 1)
    if (player == 1):
        print('玩家出了:攻')
    elif (player == 2):
        print('玩家出了:防')
    elif (player == 3):
        print('玩家出了:破')
    else:
        print('玩家输入数字超出范围')
    if (computer == 1):
        print('计算机出了:攻')
    elif (computer == 2):
        print('计算机出了:防')
    else:
        print('计算机出了:布')
    # 判断胜负
    if (player == computer or flag):
        print('此局是平局')
        t.pencolor('gray')
        t.dot(20)
        flag = False
    elif (player == 1 and computer == 3 or player == 2 and computer == 1 or player == 3 and computer == 2):
        print('此局玩家赢')
        p_win = (p_win + 1)
        t.pencolor('darkgreen')
        t.dot(20)
    elif (player == 3 and computer == 1 or player == 1 and computer == 2 or player == 2 and computer == 3):
        print('此局电脑赢')
        c_win = (c_win + 1)
        t.pencolor('red3')
        t.dot(20)
    else:
        pass
    t.penup()
    t.forward(25)
    t.pendown()
    conut = (count + 1)
    print('-------------')

print('玩家的胜局数为', p_win)
print('计算机的胜局数为', c_win)

turtle.done()

 

【提示】

部分含有Python第三方库相关内容的作品,在海龟编辑器网页端无法运行哦!如遇到这种情况,可以打开下面的链接,下载海龟编辑器客户端:

https://python.codemao.cn


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